« Competitive Programming in Haskell: sieving with mutable arrays

Products with unordered n-tuples

Posted on June 25, 2024
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Recently, Dani Rybe wrote this really cool blog post (in turn based on this old post by Samuel Gélineau) about encoding truly unordered n-tuples in Haskell. This is something I thought about a long time ago in my work on combinatorial species, but I never came up with a way to represent them. Samuel and Dani’s solution is wonderful and clever and totally impractical, and I love it.

I won’t go into more detail than that; I’ll let you go read it if you’re interested. This blog post exists solely to respond to Dani’s statement towards the end of her post:

I’m not sure how to, for example, write a function that multiplies the inputs.

Challenge accepted!

primes :: [Int]
primes = 2 : sieve primes [3 ..]
 where
  sieve (p : ps) xs =
    let (h, t) = span (< p * p) xs
     in h ++ sieve ps (filter ((/= 0) . (`mod` p)) t)

mul :: [Int] -> Int
mul = unfuck mulU
 where
  mulU :: U n Int -> Int
  mulU = ufold 1 id (< 0) \(US neg nonNeg) ->
    mulNonNeg nonNeg * mulPos primes (abs <$> neg) * (-1) ^ ulen neg

  mulNonNeg :: U n Int -> Int
  mulNonNeg = ufold 1 id (== 0) \(US zero pos) ->
    if ulen zero > 0 then 0 else mulPos primes pos

  mulPos :: [Int] -> U n Int -> Int
  mulPos ps = ufold 1 id (== 1) \(US _ pos) -> mulGTOne ps pos

  mulGTOne :: [Int] -> U n Int -> Int
  mulGTOne (p : ps) = ufold 1 id ((== 0) . (`mod` p)) \(US divP nondivP) ->
    mulPos (p : ps) ((`div` p) <$> divP) * (p ^ ulen divP) * mulGTOne ps nondivP

Since every integer has a unique prime factorization, at each step we split the remaining numbers into those divisible by \(p\) and those not divisible by \(p\). For the ones that are, we divide out \(p\) from all of them, multiply by the appropriate power of \(p\), and recurse on what’s left; for those that are not, we move on to trying the next prime.

Dani also speculates about ubind :: U n (U m a) -> U (n :*: m) a. I believe in my heart this should be possible to implement, but after playing with it a bit, I concluded it would require an astounding feat of type-fu.

PS I’m working on getting comments set up here on my new blog… hopefully coming soon!